Quelle ParseURL.java

Sprache: JAVA

/*
* Copyright (c) 1999, Oracle and/or its affiliates. All rights reserved.
* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
*
* This code is free software; you can redistribute it and/or modify it
* under the terms of the GNU General Public License version 2 only, as
* published by the Free Software Foundation.
*
* This code is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
* FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
* version 2 for more details (a copy is included in the LICENSE file that
* accompanied this code).
*
* You should have received a copy of the GNU General Public License version
* 2 along with this work; if not, write to the Free Software Foundation,
* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
*
* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
* or visit www.oracle.com if you need additional information or have any
* questions.
*/

/* @test
* @bug 4255229
* @summary URLStreamHandler.parseURL error
*
*/
import java.io.*;
import java.net.*;

public class ParseURL {
  public static void main(String args[]) throws MalformedURLException {
    String url = new URL(new URL("http://cnn.com"), "index.html").toExternalForm();
    if (url.equalsIgnoreCase("http://cnn.com/index.html")) {
      System.err.println("Success!!");
    } else {
      throw new RuntimeException("The result is "+url+", it should be http://cnn.com/index.html");
    }
  }
}

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