/** * This diff utility is taken from: * https://github.com/Slava/diff.js * * The MIT License (MIT) * * Copyright (c) 2014 Slava * * Permission is hereby granted, free of charge, to any person obtaining a copy * of this software and associated documentation files (the "Software"), to deal * in the Software without restriction, including without limitation the rights * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell * copies of the Software, and to permit persons to whom the Software is * furnished to do so, subject to the following conditions: * * The above copyright notice and this permission notice shall be included in * all copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN * THE SOFTWARE.
*/
/** * USAGE: * diff(text1, text2);
*/
/** * Longest Common Subsequence * * @param A - sequence of atoms - Array * @param B - sequence of atoms - Array * @param equals - optional comparator of atoms - returns true or false, * if not specified, triple equals operator is used * @returns Array - sequence of atoms, one of LCSs, edit script from A to B
*/ var LCS = function (A, B, /* optional */ equals) { // We just compare atoms with default equals operator by default if (equals === undefined)
equals = function (a, b) { return a === b; };
// NOTE: all intervals from now on are both sides inclusive // Get the points in Edit Graph, one of the LCS paths goes through. // The points are located on the same diagonal and represent the middle // snake ([D/2] out of D+1) in the optimal edit path in edit graph. // @param startA, endA - substring of A we are working on // @param startB, endB - substring of B we are working on // @returns Array - [ // [x, y], - beginning of the middle snake // [u, v], - end of the middle snake // D, - optimal edit distance // LCS ] - length of LCS var findMidSnake = function (startA, endA, startB, endB) { var N = endA - startA + 1; var M = endB - startB + 1; var Max = N + M; var Delta = N - M; var halfMaxCeil = (Max + 1) / 2 | 0;
var foundOverlap = false; var overlap = null;
// Maps -Max .. 0 .. +Max, diagonal index to endpoints for furthest reaching // D-path on current iteration. var V = {}; // Same but for reversed paths. var U = {};
// Special case for the base case, D = 0, k = 0, x = y = 0
V[1] = 0; // Special case for the base case reversed, D = 0, k = 0, x = N, y = M
U[Delta - 1] = N;
// Iterate over each possible length of edit script for (var D = 0; D <= halfMaxCeil; D++) { // Iterate over each diagonal for (var k = -D; k <= D && !overlap; k += 2) { // Positions in sequences A and B of furthest going D-path on diagonal k. var x, y;
// Choose from each diagonal we extend if (k === -D || (k !== D && V[k - 1] < V[k + 1])) // Extending path one point down, that's why x doesn't change, y // increases implicitly
x = V[k + 1]; else // Extending path one point to the right, x increases
x = V[k - 1] + 1;
// We can calculate the y out of x and diagonal index.
y = x - k;
if (isNaN(y) || x > N || y > M) continue;
var xx = x; // Try to extend the D-path with diagonal paths. Possible only if atoms // A_x match B_y while (x < N && y < M // if there are atoms to compare
&& equals(A[startA + x], B[startB + y])) {
x++; y++;
}
// We can safely update diagonal k, since on every iteration we consider // only even or only odd diagonals and the result of one depends only on // diagonals of different iteration.
V[k] = x;
// Check feasibility, Delta is checked for being odd. if ((Delta & 1) === 1 && inRange(k, Delta - (D - 1), Delta + (D - 1))) // Forward D-path can overlap with reversed D-1-path if (V[k] >= U[k]) // Found an overlap, the middle snake, convert X-components to dots
overlap = [xx, x].map(toPoint, k); // XXX ES5
}
if (overlap) var SES = D * 2 - 1;
// Iterate over each diagonal for reversed case for (var k = -D; k <= D && !overlap; k += 2) { // The real diagonal we are looking for is k + Delta var K = k + Delta; var x, y; if (k === D || (k !== -D && U[K - 1] < U[K + 1]))
x = U[K - 1]; else
x = U[K + 1] - 1;
y = x - K; if (isNaN(y) || x < 0 || y < 0) continue; var xx = x; while (x > 0 && y > 0 && equals(A[startA + x - 1], B[startB + y - 1])) {
x--; y--;
}
U[K] = x;
if (overlap) {
SES = SES || D * 2; // Remember we had offset of each sequence? for (var i = 0; i < 2; i++) for (var j = 0; j < 2; j++)
overlap[i][j] += [startA, startB][j] - i; return overlap.concat([ SES, (Max - SES) / 2 ]);
}
}
};
var lcsAtoms = []; var lcs = function (startA, endA, startB, endB) { var N = endA - startA + 1; var M = endB - startB + 1;
if (N > 0 && M > 0) { var middleSnake = findMidSnake(startA, endA, startB, endB); // A[x;u] == B[y,v] and is part of LCS var x = middleSnake[0][0], y = middleSnake[0][1]; var u = middleSnake[1][0], v = middleSnake[1][1]; var D = middleSnake[2];
if (D > 1) {
lcs(startA, x - 1, startB, y - 1); if (x <= u) {
[].push.apply(lcsAtoms, A.slice(x, u + 1));
}
lcs(u + 1, endA, v + 1, endB);
} elseif (M > N)
[].push.apply(lcsAtoms, A.slice(startA, endA + 1)); else
[].push.apply(lcsAtoms, B.slice(startB, endB + 1));
}
};
// Helpers var inRange = function (x, l, r) { return (l <= x && x <= r) || (r <= x && x <= l);
};
// Takes X-component as argument, diagonal as context, // returns array-pair of form x, y var toPoint = function (x) { return [x, x - this]; // XXX context is not the best way to pass diagonal
};
// Wrappers
LCS.StringLCS = function (A, B) { return LCS(A.split(''), B.split('')).join('');
};
/** * Diff sequence * * @param A - sequence of atoms - Array * @param B - sequence of atoms - Array * @param equals - optional comparator of atoms - returns true or false, * if not specified, triple equals operator is used * @returns Array - sequence of objects in a form of: * - operation: one of "none", "add", "delete" * - atom: the atom found in either A or B * Applying operations from diff sequence you should be able to transform A to B
*/ function diff(A, B, equals) { // We just compare atoms with default equals operator by default if (equals === undefined)
equals = function (a, b) { return a === b; };
var diff = []; var i = 0, j = 0; var N = A.length, M = B.length, K = 0;
while (i < N && j < M && equals(A[i], B[j]))
i++, j++;
while (i < N && j < M && equals(A[N-1], B[M-1]))
N--, M--, K++;
var lcs = LCS(A.slice(i, N), B.slice(j, M), equals);
for (var k = 0; k < lcs.length; k++) { var atom = lcs[k]; var ni = customIndexOf.call(A, atom, i, equals); var nj = customIndexOf.call(B, atom, j, equals);
// XXX ES5 map // Delete unmatched atoms from A
[].push.apply(diff, A.slice(i, ni).map(function (atom) { return { operation: "delete", atom: atom };
}));
// Add unmatched atoms from B
[].push.apply(diff, B.slice(j, nj).map(function (atom) { return { operation: "add", atom: atom };
}));
// Add the atom found in both sequences
diff.push({ operation: "none", atom: atom });
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