* Standard COBOL (file "CDR009.SCO") calling SQL * procedures in file "CDR009.MCO"
**************************************************************** * * COMMENT SECTION * * DATE 1987/12/07 STANDARD COBOL LANGUAGE * NIST SQL VALIDATION TEST SUITE V6.0 * DISCLAIMER: * This program was written by employees of NIST to test SQL * implementations for conformance to the SQL standards. * NIST assumes no responsibility for any party's use of * this program. * * CDR009.SCO * WRITTEN BY: SUN DAJUN * TRANSLATED AUTOMATICALLY FROM EMBEDDED COBOL BY CHRIS SCHANZLE * * THIS ROUTINE TESTS THE REFERENCE INTEGRITY CONSTRAINT FOR * SQL. * * REFERENCES * AMERICAN NATIONAL STANDARD database language - SQL * with Integrity Enhancement * * SECTION 6.6 <unique constraint definition> * <unique constraint definition>::= * <unique specifition>(<unique column * list>) * <unique specifition>::= UNIQUE|PRIMARY KEY * * SECTION 6.7 <referential constraint definition> * <referential constraint definition>::= * FOREIGN KEY (<referencing columns>) * <references specification> * <references specification>::= * REFERENCES <referenced table and columns> * <referencing columns>::= * <reference column list> * <refereced table and columns>::= * <table name>((<reference column list> * <reference column list>::= * <column name>({,<column name>}...) * ****************************************************************
MOVE"SUN"TO uid CALL"AUTHID"USING uid MOVE"not logged in, not"TO uidx CALL"AUTHCK"USING SQLCODE uidx MOVE SQLCODE TO SQL-COD if (uid NOT = uidx) then DISPLAY"ERROR: User " uid " expected." DISPLAY"User " uidx " connected." DISPLAY" " STOPRUN END-IF
MOVE 0 TO errcnt DISPLAY "SQL Test Suite, V6.0, Module COBOL, cdr009.sco" DISPLAY" " DISPLAY "59-byte ID" DISPLAY"TEd Version #" DISPLAY" " * date_time print * ACCEPT TO-DAY FROMDATE ACCEPT THE-TIME FROMTIME DISPLAY"Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME
******************** BEGIN TEST0327 ******************* *This program inserts two rows into PRIMARY KEY TABLE *-- STAFF3, these two rows have the same value 'E1' in *PRIMARY COLUMN and there is no (E1,*,*) in referen- *cing table.
DISPLAY" INSERT INTO STAFF3" DISPLAY" VALUES('E1','Alice',12,'Deale');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count1" DISPLAY" FROM STAFF3;" DISPLAY" " DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" VALUES('E1','Tom',12,'Newyork');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count2" DISPLAY" FROM STAFF3;" MOVE 0 TO count1 MOVE 0 TO count2 * EXEC SQL DELETE FROM WORKS3; CALL"SUB1"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB2"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * VALUES('E1','Alice',12,'Deale') END-EXEC CALL"SUB3"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL SELECT COUNT(*) INTO:count1 * FROM STAFF3 END-EXEC CALL"SUB4"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD
* EXEC SQL INSERT INTO STAFF3 * VALUES('E1','Tom',12,'Newyork') END-EXEC CALL"SUB5"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO:count2 * FROM STAFF3 END-EXEC CALL"SUB6"USING SQLCODE count2 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" SQLCODE of second INSERT not equal to 0." DISPLAY" count1 is 1" DISPLAY" count2 is 1" DISPLAY" Your answer is :" DISPLAY" SQLCOD of second INSERT is ", code1 DISPLAY" count1 is ", count1 DISPLAY" count2 is ", count2 if (code1 NOT = 0 AND count1 = 1 AND count2 = 1) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0327','pass','MCO') END-EXEC CALL"SUB7"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0327','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB8"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr009.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB9"USING SQLCODE MOVE SQLCODE TO SQL-COD **************** END TEST 0327 **********
******************** BEGIN TEST0328 ******************* *This program updates a row in PRIMARY KEY TABLE *-- STAFF3, set (E2,*,*,*) to (E9,*,*,*) ,there *are (E2,*,*) In WORKS3.
DISPLAY" TEST0328 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" UPDATE STAFF3" DISPLAY" SET EMPNUM='E9'" DISPLAY" WHERE EMPNUM='E2';" DISPLAY"code1 = SQLCODE;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM STAFF3" DISPLAY" WHERE EMPNUM = 'E2';" * EXEC SQL DELETE FROM WORKS3; CALL"SUB10"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB11"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB12"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB13"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO PROJ3 * SELECT * FROM PROJ END-EXEC CALL"SUB14"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * SELECT * FROM WORKS END-EXEC CALL"SUB15"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE STAFF3 * SET EMPNUM = 'E9' * WHERE EMPNUM = 'E2' END-EXEC CALL"SUB16"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM STAFF3 * WHERE EMPNUM = 'E2' END-EXEC CALL"SUB17"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct result is code1 not equal 0" DISPLAY" count1 = 1" DISPLAY" Your answer is code1=", code1 DISPLAY" count1 = ", count1 if (code1 < 0 AND count1 = 1) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0328','pass','MCO') END-EXEC CALL"SUB18"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0328','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB19"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr009.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB20"USING SQLCODE MOVE SQLCODE TO SQL-COD ******************** END TEST0328 *************************
******************** BEGIN TEST0329 ******************* *This program updates a row in PRIMARY KEY TABLE *-- STAFF3, that cause two rows have the same value *'E1' in PRIMARY COLUMN.
DISPLAY" TEST0329 " DISPLAY" PRIMARY KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" VALUES('E1','Alice',45,'Deale');" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" VALUES('E2','Tom',45,'Deale');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count1" DISPLAY" FROM STAFF3;" DISPLAY" " DISPLAY" UPDATE STAFF3" DISPLAY" SET EMPNUM = 'E1'" DISPLAY" WHERE EMPNUM = 'E2';" DISPLAY" " MOVE 0 TO count1 MOVE 0 TO count2 * EXEC SQL DELETE FROM WORKS3; CALL"SUB21"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB22"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * VALUES('E1','Alice',45,'Deale') END-EXEC CALL"SUB23"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * VALUES('E2','Tom',45,'Deale') END-EXEC CALL"SUB24"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL SELECT COUNT(*) INTO:count1 * FROM STAFF3 END-EXEC CALL"SUB25"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD
* EXEC SQL UPDATE STAFF3 * SET EMPNUM = 'E1' * WHERE EMPNUM = 'E2' END-EXEC CALL"SUB26"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO:count2 * FROM STAFF3 * WHERE EMPNUM = 'E2' END-EXEC CALL"SUB27"USING SQLCODE count2 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" SQLCODE of second INSERT not equal to 0." DISPLAY" count1 is 2" DISPLAY" count2 is 1" DISPLAY" Your answer is :" DISPLAY" SQLCOD of second INSERT is ", code1 DISPLAY" count1 is ", count1 DISPLAY" count2 is ", count2 if (code1 NOT = 0 AND count1 = 2 AND count2 = 1) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0329','pass','MCO') END-EXEC CALL"SUB28"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0329','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB29"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr009.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB30"USING SQLCODE MOVE SQLCODE TO SQL-COD **************** END TEST 0329 **********
******************** BEGIN TEST0330 ******************* *This test update a row or rows on FOREIGN KEY *column in table WORKS3,set those rows (E1,*,*) to *(E9,*,*),but there is not a row ('E9',*,*,*) in * PRIMARY TABLE -- STAFF3, this will bring about an * ERROR.
DISPLAY" TEST0330 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM PROJ3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" INSERT INTO PROJ3" DISPLAY" SELECT * FROM PROJ;" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" SELECT * FROM WORKS;" DISPLAY" " DISPLAY" UPDATE WORKS3" DISPLAY" SET EMPNUM='E9'" DISPLAY" WHERE EMPNUM='E2';" DISPLAY"code1 = SQLCODE;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM WORKS3" DISPLAY" WHERE EMPNUM = 'E2';" * EXEC SQL DELETE FROM WORKS3; CALL"SUB31"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB32"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB33"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB34"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO PROJ3 * SELECT * FROM PROJ END-EXEC CALL"SUB35"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * SELECT * FROM WORKS END-EXEC CALL"SUB36"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE WORKS3 * SET EMPNUM = 'E9' * WHERE EMPNUM = 'E2' END-EXEC CALL"SUB37"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM WORKS3 * WHERE EMPNUM = 'E2' END-EXEC CALL"SUB38"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct result is code1 not equal 0" DISPLAY" count1 = 2" DISPLAY" Your answer is code1=", code1 DISPLAY" count1 = ", count1 if (code1 NOT = 0 AND count1 = 2) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0330','pass','MCO') END-EXEC CALL"SUB39"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0330','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB40"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr009.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB41"USING SQLCODE MOVE SQLCODE TO SQL-COD ******************** END TEST0330 *************************
******************** BEGIN TEST0331 ****************** *This test update a row or rows on FOREIGN KEY *column in table WORKS3,set those rows (E1,*,*) to *(E2,*,*),and there are such a row (E2,-,-,-) in * PRIMARY TABLE -- STAFF3 and rows (E2,*,*) in *WORKS3.
DISPLAY" TEST0331 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM PROJ3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" INSERT INTO PROJ3" DISPLAY" SELECT * FROM PROJ;" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" SELECT * FROM WORKS;" DISPLAY" " DISPLAY" UPDATE WORKS3" DISPLAY" SET EMPNUM='E2'" DISPLAY" WHERE EMPNUM='E1';" DISPLAY"code1 = SQLCODE;" DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM WORKS3" DISPLAY" WHERE EMPNUM = 'E1';" MOVE 0 TO count1 * EXEC SQL DELETE FROM WORKS3; CALL"SUB42"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB43"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB44"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB45"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO PROJ3 * SELECT * FROM PROJ END-EXEC CALL"SUB46"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * SELECT * FROM WORKS END-EXEC CALL"SUB47"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE WORKS3 * SET EMPNUM = 'E2' * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB48"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM WORKS3 * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB49"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct result is code1 equal 0" DISPLAY" count1 = 0" DISPLAY" Your answer is code1=", code1 DISPLAY" count1 = ", count1 if (code1 = 0 AND count1 = 0) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0331','pass','MCO') END-EXEC CALL"SUB50"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0331','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB51"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr009.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB52"USING SQLCODE MOVE SQLCODE TO SQL-COD ******************** END TEST0331 *************************
**** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0 STOPRUN.
* **** Procedures for PERFORM statements
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