/* Some architecture set descriptions include special "ordered" memory */ /* operations. As far as we can tell, no existing processors actually */ /* require those. Nor does it appear likely that future processors */ /* will. */ #include"../ordered.h"
/* GCC will not guarantee the alignment we need, use four lock words */ /* and select the correctly aligned datum. See the glibc 2.3.2 */ /* linuxthread port for the original implementation. */ struct AO_pa_clearable_loc { int data[4];
};
#undef AO_TS_INITIALIZER #define AO_TS_t struct AO_pa_clearable_loc #define AO_TS_INITIALIZER { { 1, 1, 1, 1 } } /* Switch meaning of set and clear, since we only have an atomic clear */ /* instruction. */ typedefenum {AO_PA_TS_set = 0, AO_PA_TS_clear = 1} AO_PA_TS_val; #define AO_TS_VAL_t AO_PA_TS_val #define AO_TS_CLEAR AO_PA_TS_clear #define AO_TS_SET AO_PA_TS_set
/* The hppa only has one atomic read and modify memory operation, */ /* load and clear, so hppa spinlocks must use zero to signify that */ /* someone is holding the lock. The address used for the ldcw */ /* semaphore must be 16-byte aligned. */ #define AO_ldcw(a, ret) \
__asm__ __volatile__("ldcw 0(%2), %0" \
: "=r" (ret), "=m" (*(a)) : "r" (a))
/* Because malloc only guarantees 8-byte alignment for malloc'd data, */ /* and GCC only guarantees 8-byte alignment for stack locals, we can't */ /* be assured of 16-byte alignment for atomic lock data even if we */ /* specify "__attribute ((aligned(16)))" in the type declaration. So, */ /* we use a struct containing an array of four ints for the atomic lock */ /* type and dynamically select the 16-byte aligned int from the array */ /* for the semaphore. */ #define AO_PA_LDCW_ALIGNMENT 16 #define AO_ldcw_align(addr) \
((volatileunsigned *)(((unsignedlong)(addr) \
+ (AO_PA_LDCW_ALIGNMENT - 1)) \
& ~(AO_PA_LDCW_ALIGNMENT - 1)))
/* Works on PA 1.1 and PA 2.0 systems */
AO_INLINE AO_TS_VAL_t
AO_test_and_set_full(volatile AO_TS_t * addr)
{ volatileunsignedint ret; volatileunsigned *a = AO_ldcw_align(addr);
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