* Standard COBOL (file "CDR008.SCO") calling SQL * procedures in file "CDR008.MCO"
**************************************************************** * * COMMENT SECTION * * DATE 1989/04/07 STANDARD COBOL LANGUAGE * NIST SQL VALIDATION TEST SUITE V6.0 * DISCLAIMER: * This program was written by employees of NIST to test SQL * implementations for conformance to the SQL standards. * NIST assumes no responsibility for any party's use of * this program. * * CDR008.SCO * WRITTEN BY: SUN DAJUN * TRANSLATED AUTOMATICALLY FROM EMBEDDED COBOL BY CHRIS SCHANZLE * * THIS ROUTINE TESTS THE REFERENTIAL INTEGRITY CONSTRAINT FOR * SQL. * * REFERENCES * AMERICAN NATIONAL STANDARD database language - SQL * with Integrity Enhancement * * SECTION 6.7 <referential constraint definition> * <referential constraint definition>::= * FOREIGN KEY (<referencing columns>) * <references specification> * <references specification>::= * REFERENCES <referenced table and columns> * <referencing columns>::= * <reference column list> * <refereced table and columns>::= * <table name>((<reference column list> * <reference column list>::= * <column name>({,<column name>}...) * ****************************************************************
MOVE"SUN"TO uid CALL"AUTHID"USING uid MOVE"not logged in, not"TO uidx CALL"AUTHCK"USING SQLCODE uidx MOVE SQLCODE TO SQL-COD if (uid NOT = uidx) then DISPLAY"ERROR: User " uid " expected." DISPLAY"User " uidx " connected." DISPLAY" " STOPRUN END-IF
MOVE 0 TO errcnt DISPLAY "SQL Test Suite, V6.0, Module COBOL, cdr008.sco" DISPLAY" " DISPLAY "59-byte ID" DISPLAY"TEd Version #" DISPLAY" " * date_time print * ACCEPT TO-DAY FROMDATE ACCEPT THE-TIME FROMTIME DISPLAY"Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME ******************** BEGIN TEST0323 *******************
*This test inserts a row (E1,P1,40) in FOREIGN KEY *TABLE -- WORKS3, there have been such value (*,P1,*) *in WORKS3
DISPLAY" TEST0323 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" DELETE FROM PROJ3;" DISPLAY" " DISPLAY" INSERT INTO PROJ3" DISPLAY" VALUES
- " ('P1','MASS','Design',10000,'Deale');" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" VALUES ('E1','P1',40);" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" VALUES ('E2','P1',40);" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count1" DISPLAY" FROM WORKS3;" * EXEC SQL DELETE FROM WORKS3; CALL"SUB1"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB2"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB3"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO PROJ3 * VALUES ('P1','MASS','Design',10000,'Deale') END-EXEC CALL"SUB4"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB5"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * VALUES ('E1','P1',40) END-EXEC CALL"SUB6"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * VALUES ('E2','P1',40) END-EXEC CALL"SUB7"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO:count1 * FROM WORKS3 END-EXEC CALL"SUB8"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" SQLCODE is equal to 0." DISPLAY" count1 is 2" DISPLAY" Your answer is :" DISPLAY" SQLCOD of second insert is ", code1 DISPLAY" count1 is ", count1 if (code1 = 0 AND count1 = 2) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0323','pass','MCO') END-EXEC CALL"SUB9"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0323','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB10"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr008.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB11"USING SQLCODE MOVE SQLCODE TO SQL-COD ************************ END TEST0323 ************************
******************** BEGIN TEST0324 ******************* *This test inserts rows into FOREIGN KEY *TABLE -- WORKS3, there have been such a row *(P1,-,-,-,-) in PROJ,but no (P2,-,-,-,-) in PROJ
DISPLAY" TEST0324 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" DELETE FROM PROJ3;" DISPLAY" " DISPLAY" INSERT INTO PROJ3" DISPLAY" VALUES
- " ('P1','MASS','Design',10000,'Deale');" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" VALUES ('E1','P1',40);" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" VALUES ('E2','P2',40);" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count1" DISPLAY" FROM WORKS3" DISPLAY" WHERE PNUM = 'P2';" COMPUTE count1 = -1 * EXEC SQL DELETE FROM WORKS3; CALL"SUB12"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB13"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB14"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO PROJ3 * VALUES ('P1','MASS','Design',10000,'Deale') END-EXEC CALL"SUB15"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB16"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * VALUES ('E1','P1',40) END-EXEC CALL"SUB17"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * VALUES ('E2','P2',40) END-EXEC CALL"SUB18"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO:count1 * FROM WORKS3 * WHERE PNUM = 'P2' END-EXEC CALL"SUB19"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" SQLCODE is less than 0." DISPLAY" count1 is 0" DISPLAY" Your answer is :" DISPLAY" SQLCOD of second insert is ", code1 DISPLAY" count1 is ", count1 if (code1 < 0 AND count1 = 0) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0324','pass','MCO') END-EXEC CALL"SUB20"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0324','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB21"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr008.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB22"USING SQLCODE MOVE SQLCODE TO SQL-COD ************************ END TEST0324 ************************
******************** BEGIN TEST0325 ********************* *This test deletes a row (E1,-,-,-) from PRIMARY KEY *TABLE -- STAFF3, but there are such rows (E1,*,*) in *FOREIGN KEY TABLE -- WORK3, this should be an ERROR.
DISPLAY" TEST0325 " DISPLAY" REFERENTIAL INTEGRITY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM PROJ3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" INSERT INTO PROJ3" DISPLAY" SELECT * FROM PROJ;" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" SELECT * FROM WORKS;" DISPLAY" " DISPLAY" DELETE FROM STAFF3" DISPLAY" WHERE EMPNUM='E1';" DISPLAY" " DISPLAY"code1 = SQLCODE" DISPLAY" " DISPLAY" SELECT EMPNUM INTO :EMPNO1" DISPLAY" FROM STAFF3" DISPLAY" WHERE EMPNUM = 'E1';" * EXEC SQL DELETE FROM WORKS3; CALL"SUB23"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB24"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB25"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB26"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO PROJ3 * SELECT * FROM PROJ END-EXEC CALL"SUB27"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO WORKS3 * SELECT * FROM WORKS END-EXEC CALL"SUB28"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3 * WHERE EMPNUM='E1' END-EXEC CALL"SUB29"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 MOVE"NV"TO EMPNO1 * EXEC SQL SELECT EMPNUM INTO :EMPNO1 * FROM STAFF3 * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB30"USING SQLCODE EMPNO1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct result is code1 not equal to 0" DISPLAY" Your answer is code1=", code1 if (code1 NOT = 0 AND EMPNO1 = "E1") then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0325','pass','MCO') END-EXEC CALL"SUB31"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0325','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB32"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr008.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB33"USING SQLCODE MOVE SQLCODE TO SQL-COD ****************** END TEST0325 ********************
******************** BEGIN TEST0326 ********************* *This test set a row (E1,-,-,-) in PRIMARY KEY TABLE *-- STAFF3 to (E9,-,-,-), there is no such a row *(E1,*,*) in FOREIGN KEY TABLE -- WORK3.
DISPLAY" TEST0326 " DISPLAY" REFERENTIAL INTEGRITY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" UPDATE STAFF3" DISPLAY" SET EMPNUM = 'E9'" DISPLAY" WHERE EMPNUM = 'E1';" DISPLAY" " DISPLAY"code1 = SQLCODE" DISPLAY" " DISPLAY" SELECT EMPNUM INTO :EMPNO1" DISPLAY" FROM STAFF3" DISPLAY" WHERE EMPNUM = 'E1';" * EXEC SQL DELETE FROM WORKS3; CALL"SUB34"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB35"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB36"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE STAFF3 * SET EMPNUM = 'E9' * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB37"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 MOVE"NV"TO EMPNO1 * EXEC SQL SELECT EMPNUM INTO :EMPNO1 * FROM STAFF3 * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB38"USING SQLCODE EMPNO1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct result is code1 equal to 0" DISPLAY" Your answer is code1=", code1 if (code1 = 0 AND (EMPNO1 = "NV")) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0326','pass','MCO') END-EXEC CALL"SUB39"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0326','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB40"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr008.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB41"USING SQLCODE MOVE SQLCODE TO SQL-COD ****************** END TEST0326 ********************
**** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0 STOPRUN.
* **** Procedures for PERFORM statements
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