/* * Copyright (c) 2018, 2021, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions.
*/
/** * Utility class containing conversions between strings, arrays, numeric * values, and other types.
*/
publicclass Convert {
// Expand a single byte to a byte array publicstaticbyte[] byteToByteArray(byte v, int length) { byte[] result = newbyte[length];
result[0] = v; return result;
}
/* * Convert a hexadecimal string to the corresponding little-ending number * as a BigInteger. The clearHighBit argument determines whether the most * significant bit of the highest byte should be set to 0 in the result.
*/ publicstatic
BigInteger hexStringToBigInteger(boolean clearHighBit, String str) {
BigInteger result = BigInteger.ZERO; for (int i = 0; i < str.length() / 2; i++) { int curVal = Character.digit(str.charAt(2 * i), 16);
curVal <<= 4;
curVal += Character.digit(str.charAt(2 * i + 1), 16); if (clearHighBit && i == str.length() / 2 - 1) {
curVal &= 0x7F;
}
result = result.add(BigInteger.valueOf(curVal).shiftLeft(8 * i));
} return result;
}
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