Quelle  ListUtilities.thy

section ‹ListUtilities›

text ‹
 \file{ListUtilities} defines a (proper) prefix relation for lists, and proves some
 additional lemmata, mostly about lists.
 ›

theory ListUtilities
imports Main
begin

subsection ‹List Prefixes›

inductive prefixList ::
  "'a list ==> 'a list ==> bool"
where
  "prefixList [] (x # xs)"
| "prefixList xa xb ==> prefixList (x # xa) (x # xb)"

lemma PrefixListHasTail:
fixes 
  l1 :: "'a list" and
  l2 :: "'a list"
assumes
  "prefixList l1 l2"
shows
  "∃ l . l2 = l1 @ l ∧ l ≠ []"
using assms by (induct rule: prefixList.induct, auto)

lemma PrefixListMonotonicity:
fixes 
  l1 :: "'a list" and
  l2 :: "'a list"
assumes
  "prefixList l1 l2"
shows
  "length l1 < length l2"
using assms by (induct rule: prefixList.induct, auto)

lemma TailIsPrefixList : 
fixes 
  l1 :: "'a list" and
  tail :: "'a list"
assumes "tail ≠ []"
shows "prefixList l1 (l1 @ tail)"
using assms
proof (induct l1, auto)
  have "∃ x xs . tail = x # xs"
    using assms by (metis neq_Nil_conv)
  thus "prefixList [] tail"
    using assms  by (metis prefixList.intros(1))
next
  fix a l1
  assume "prefixList l1 (l1 @ tail)"
  thus "prefixList (a # l1) (a # l1 @ tail)"
    by (metis prefixList.intros(2))
qed

lemma PrefixListTransitive:
fixes 
  l1 :: "'a list" and
  l2 :: "'a list" and
  l3 :: "'a list"
assumes
  "prefixList l1 l2"
  "prefixList l2 l3"
shows
  "prefixList l1 l3"
using assms
proof -
  from assms(1) have "∃ l12 . l2 = l1 @ l12 ∧ l12 ≠ []" 
    using PrefixListHasTail by auto
  then obtain l12 where Extend1: "l2 = l1 @ l12 ∧ l12 ≠ []" by blast
  from assms(2) have Extend2: "∃ l23 . l3 = l2 @ l23 ∧ l23 ≠ []" 
    using PrefixListHasTail by auto
  then obtain l23 where Extend2: "l3 = l2 @ l23 ∧ l23 ≠ []" by blast
  have "l3 = l1 @ (l12 @ l23) ∧ (l12 @ l23) ≠ []" 
    using Extend1 Extend2 by simp
  hence "∃ l . l3 = l1 @ l ∧ l ≠ []" by blast
  thus "prefixList l1 l3" using TailIsPrefixList by auto  
qed

subsection ‹Lemmas for lists and nat predicates›

lemma NatPredicateTippingPoint:
fixes 
  n2 Pr
assumes
  Min:     "0 < n2" and
  Pr0:     "Pr 0" and
  NotPrN2: "¬Pr n2"
shows
  "∃n<n2. Pr n ∧ ¬Pr (Suc n)"                       
proof (rule classical, simp)
  assume Asm: "∀n. Pr n ⟶ n < n2 ⟶ Pr (Suc n)"
  have "∧n. n < n2 ==> Pr n"
  proof-
    fix n
    show "n < n2 ==> Pr n"
    by (induct n, auto simp add: Pr0 Asm)
  qed
  hence False
    using Asm[rule_format, of "n2 - 1"] Min NotPrN2 by auto
  thus ?thesis by auto
qed

lemma MinPredicate:
fixes 
  P::"nat ==> bool"
assumes
  "∃ n . P n"
shows 
  "(∃ n0 . (P n0) ∧ (∀ n' . (P n') ⟶ (n' ≥ n0)))"
using assms
by (metis LeastI2_wellorder Suc_n_not_le_n)

text ‹
 The lemma \isb{MinPredicate2} describes one case of \isb{MinPredicate}
 where the aforementioned smallest element is zero.
 ›

lemma MinPredicate2:
fixes
  P::"nat ==> bool"
assumes
 "∃ n . P n"
shows
  "∃ n0 . (P n0) ∧ (n0 = 0 ∨ ¬ P (n0 - 1))"
using assms MinPredicate
by (metis add_diff_cancel_right' diff_is_0_eq diff_mult_distrib mult_eq_if)

text ‹
 \isb{PredicatePairFunction} allows to obtain functions mapping two arguments
 to pairs from 4-ary predicates which are left-total on their first
 two arguments.
 ›

lemma PredicatePairFunction: 
fixes
  P::"'a ==> 'b ==> 'c ==> 'd ==> bool"
assumes
  A1: "∀x1 x2 . ∃y1 y2 . (P x1 x2 y1 y2)"
shows 
  "∃f . ∀x1 x2 . ∃y1 y2 .
    (f x1 x2) = (y1, y2)
    ∧ (P x1 x2 (fst (f x1 x2)) (snd (f x1 x2)))"
proof -
  define P' where "P' x y = P (fst x) (snd x) (fst y) (snd y)" for x y
  hence "∀x. ∃y. P' x y" using A1 by auto
  hence "∃f. ∀x. P' x (f x)" by metis
  then obtain f where "∀x. P' x (f x)" by blast
  moreover define f' where "f' x1 x2 = f (x1, x2)" for x1 x2
  ultimately have "∀x. P' x (f' (fst x) (snd x))" by auto
  hence "∃f'. ∀x. P' x (f' (fst x) (snd x))" by blast
  thus ?thesis using P'_def by auto
qed           

lemma PredicatePairFunctions2: 
fixes
  P::"'a ==> 'b ==> 'c ==> 'd ==> bool"
assumes
  A1: "∀x1 x2 . ∃y1 y2 . (P x1 x2 y1 y2)"
obtains f1 f2  where
  "∀x1 x2 . ∃y1 y2 .
    (f1 x1 x2) = y1 ∧ (f2 x1 x2) = y2
    ∧ (P x1 x2 (f1 x1 x2) (f2 x1 x2))"
proof (cases thesis, auto)
  assume ass: "∧f1 f2. ∀x1 x2. P x1 x2 (f1 x1 x2) (f2 x1 x2) ==> False"
  obtain f where F: "∀x1 x2. ∃y1 y2. f x1 x2 = (y1, y2) ∧ P x1 x2 (fst (f x1 x2)) (snd (f x1 x2))"
    using PredicatePairFunction[OF A1] by blast
  define f1 where "f1 x1 x2 = fst (f x1 x2)" for x1 x2
  define f2 where "f2 x1 x2 = snd (f x1 x2)" for x1 x2
  show False
    using ass[of f1 f2] F unfolding f1_def f2_def by auto
qed

lemma PredicatePairFunctions2Inv: 
fixes
  P::"'a ==> 'b ==> 'c ==> 'd ==> bool"
assumes
  A1: "∀x1 x2 . ∃y1 y2 . (P x1 x2 y1 y2)"
obtains f1 f2  where
  "∀x1 x2 . (P x1 x2 (f1 x1 x2) (f2 x1 x2))"
using PredicatePairFunctions2[OF A1] by auto

lemma SmallerMultipleStepsWithLimit:
fixes
  k A limit
assumes
  "∀ n ≥ limit . (A (Suc n)) < (A n)"
shows
  "∀ n ≥ limit . (A (n + k)) ≤ (A n) - k"
proof(induct k,auto)
  fix n k
  assume IH: "∀n≥limit. A (n + k) ≤ A n - k" "limit ≤ n"
  hence "A (Suc (n + k)) < A (n + k)" using assms by simp 
  hence "A (Suc (n + k)) < A n - k" using IH by auto
  thus "A (Suc (n + k)) ≤ A n - Suc k" 
    by (metis Suc_lessI add_Suc_right add_diff_cancel_left' 
       less_diff_conv less_or_eq_imp_le add.commute)
qed

lemma PrefixSameOnLow:
fixes
  l1 l2
assumes
  "prefixList l1 l2"
shows
  "∀ index < length l1 . l1 ! index = l2 ! index"
using assms
proof(induct rule: prefixList.induct, auto)
  fix xa xb ::"'a list" and x index
  assume AssumpProof: "prefixList xa xb" 
        "∀index < length xa. xa ! index = xb ! index"
        "prefixList l1 l2" "index < Suc (length xa)"
  show "(x # xa) ! index = (x # xb) ! index" using AssumpProof
  proof(cases "index = 0", auto)
  qed
qed

lemma KeepProperty:
fixes
  P Q low
assumes
  "∀ i ≥ low . P i ⟶ (P (Suc i) ∧ Q i)" "P low"
shows
  "∀ i ≥ low . Q i"
using assms
proof(clarify)
  fix i
  assume Assump:
    "∀i≥low. P i ⟶ P (Suc i) ∧ Q i"
    "P low"
    "low ≤ i"
  hence "∀i≥low. P i ⟶ P (Suc i)" by blast
  hence "∀ i ≥ low . P i" using Assump(2) by (metis dec_induct)
  hence "P i" using Assump(3) by blast
  thus "Q i" using Assump by blast
qed

lemma ListLenDrop: 
fixes
  i la lb
assumes
  "i < length lb"
  "i ≥ la"
shows
  "lb ! i ∈ set (drop la lb)" 
using assms
  by (metis Cons_nth_drop_Suc in_mono list.set_intros(1) set_drop_subset_set_drop) 

lemma DropToShift:
fixes
  l i list
assumes
  "l + i < length list"
shows
  "(drop l list) ! i = list ! (l + i)"
using assms
by (induct l, auto)

lemma SetToIndex:
fixes
  a and liste::"'a list"
assumes
  AssumpSetToIndex: "a ∈ set liste"
shows
  "∃ index < length liste . a = liste ! index"
proof -
  have LenInduct:
    "∧xs. ∀ys. length ys < length xs ⟶ a ∈ set ys
          ⟶ (∃index<length ys. a = ys ! index)
          ==> a ∈ set xs ⟶ (∃index<length xs. a = xs ! index)" 
  proof(auto)
    fix xs
    assume AssumpLengthInduction: 
      "∀ys. length ys < length xs ⟶ a ∈ set ys
      ⟶ (∃index<length ys. a = ys ! index)" "a ∈ set xs"
    have "∃ x xs' . xs = x#xs'" using AssumpLengthInduction(2) 
      by (metis ListMem.cases ListMem_iff)
    then obtain x xs' where XSSplit: "xs = x#xs'" by blast
    hence "a ∈ insert x (set xs')" using set_simps AssumpLengthInduction 
      by simp
    hence "a = x ∨ a ∈ set xs'" by simp
    thus "∃index<length xs. a = xs ! index"
    proof(cases "a = x",auto)
      show "∃index<length xs. x = xs ! index" using XSSplit by auto
    next
      assume AssumpCases: "a ∈ set xs'" "a ≠ x"
      have "length xs' < length xs" using XSSplit by simp
      hence "∃index<length xs'. a = xs' ! index" 
        using AssumpLengthInduction(1) AssumpCases(1) by simp
      thus "∃index<length xs. a = xs ! index" using XSSplit by auto
    qed
  qed
  thus "∃ index < length liste . a = liste ! index" 
    using length_induct[of 
      "λl. a ∈ set l ⟶ (∃ index < length l . a = l ! index)" "liste"] 
    AssumpSetToIndex by blast
qed

lemma DropToIndex:
fixes
  a::"'a" and l liste 
assumes
  AssumpDropToIndex: "a ∈ set (drop l liste)"
shows
  "∃ i ≥ l . i < length liste ∧ a = liste ! i"
proof-
  have "∃ index < length (drop l liste) . a = (drop l liste) ! index"
    using AssumpDropToIndex SetToIndex[of "a" "drop l liste"] by blast
  then obtain index where Index: "index < length (drop l liste)" 
    "a = (drop l liste) ! index" by blast
  have "l + index < length liste" using Index(1) 
    by (metis length_drop less_diff_conv add.commute)
  hence "a = liste ! (l + index)" 
    using DropToShift[of "l" "index"] Index(2) by blast
  thus "∃i≥l. i < length liste ∧ a = liste ! i" 
    by (metis ‹l + index < length liste› le_add1)
qed

end