**************************************************************** * * COMMENT SECTION * * DATE 1989/04/07 EMBEDDED COBOL LANGUAGE * NIST SQL VALIDATION TEST SUITE V6.0 * DISCLAIMER: * This program was written by employees of NIST to test SQL * implementations for conformance to the SQL standards. * NIST assumes no responsibility for any party's use of * this program. * * CDR004.PCO * WRITTEN BY: SUN DAJUN * TRANSLATED AUTOMATICALLY FROM EMBEDDED C BY CHRIS SCHANZLE * * THIS ROUTINE TESTS THE <CHECK> CONSTRAINT. * * REFERENCES * AMERICAN NATIONAL STANDARD database language - SQL * with Integrity Enhancement * * SECTION 6.8 * <check constraint definition>::= * CHECK (<search condition>) ****************************************************************
MOVE"SUN"TO uid CALL"AUTHID"USING uid MOVE"not logged in, not"TO uidx EXECSQLSELECT
USER INTO :uidx FROM SUN.ECCO END-EXEC if (uid NOT = uidx) then DISPLAY"ERROR: User " uid " expected." DISPLAY"User " uidx " connected." DISPLAY" " STOPRUN END-IF
MOVE 0 TO errcnt DISPLAY "SQL Test Suite, V6.0, Embedded COBOL, cdr004.pco" DISPLAY" " DISPLAY "59-byte ID" DISPLAY"TEd Version #" DISPLAY" " * date_time print * ACCEPT TO-DAY FROMDATE ACCEPT THE-TIME FROMTIME DISPLAY"Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME ******************** BEGIN TEST0309 ****************** *This procedure tests CHECK specification on two *columns with AND. * CHECK condition * GRADE NOT IN (5,22) AND EMPNAME LIKE 'T%'
DISPLAY" TEST0309 " DISPLAY" CHECK CONSTRAINTS " DISPLAY" SQL with Integrity Enhancement section 6.8" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF11" DISPLAY" VALUES('E1','Thomas',0,'Deale');" DISPLAY"code1 = SQLCODE;" DISPLAY" " DISPLAY" INSERT INTO STAFF11" DISPLAY" VALUES('E2','Dom',22,'Newyork');" DISPLAY"code2 = SQLCODE;" DISPLAY" " DISPLAY" INSERT INTO STAFF11" DISPLAY" VALUES('E3','Susan',11,'Hawaii');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM STAFF11;" EXECSQLDELETEFROM STAFF11 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLINSERTINTO STAFF11
VALUES('E1','Thomas',0,'Deale') END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQLINSERTINTO STAFF11
VALUES('E2','Tom',22,'Newyork') END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 EXECSQLINSERTINTO STAFF11
VALUES('E3','Susan',11,'Hawaii') END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLSELECTCOUNT(*) INTO :count1 FROM STAFF11 END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is:" DISPLAY" code1 < 0,code2 < 0,count1 = 1." DISPLAY" Your answer is:" DISPLAY" code1 = ", code1 ",code2 = ", code2 DISPLAY",count1= ", count1 if (code1 NOT = 0 AND count1 = 1 ) then EXECSQLINSERTINTO TESTREPORT
VALUES('0309','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0309','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr004.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD ****************** END TEST0309 *****************************
******************** BEGIN TEST0310 ****************** *This procedure tests if x NOT IN and NOT x IN of the *CHECK specification has the same meaning . * CHECK condition * NOT GRADE IN (5,22) on STAFF12
DISPLAY" TEST0310 " DISPLAY" CHECK CONSTRAINTS " DISPLAY" SQL with Integrity Enhancement section 6.8" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF12" DISPLAY" VALUES('E1','Thomas',0,'Deale');" DISPLAY"code1 = SQLCODE;" DISPLAY" " DISPLAY" INSERT INTO STAFF12" DISPLAY" VALUES('E2','Dom',22,'Newyork');" DISPLAY"code2 = SQLCODE;" DISPLAY" " DISPLAY" INSERT INTO STAFF12" DISPLAY" VALUES('E3','Susan',11,'Hawaii');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM STAFF12;" EXECSQLDELETEFROM STAFF12 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLINSERTINTO STAFF12
VALUES('E1','Thomas',0,'Deale') END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQLINSERTINTO STAFF12
VALUES('E2','Tom',22,'Newyork') END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 EXECSQLINSERTINTO STAFF12
VALUES('E3','Susan',11,'Hawaii') END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLSELECTCOUNT(*) INTO :count1 FROM STAFF12 END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is:" DISPLAY" code1 < 0,code2 < 0,count1 = 1." DISPLAY" Your answer is:" DISPLAY" code1 = ", code1 ",code2 = ", code2 DISPLAY",count1= ", count1 if (code1 NOT = 0 AND count1 = 1 ) then EXECSQLINSERTINTO TESTREPORT
VALUES('0310','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0310','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr004.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD ****************** END TEST0310 *****************************
******************** BEGIN TEST0311 ******************* *This test check the constraint NOT NULL in column *definition constraint. * CHECK condition * NOT NULL in EMPNAME def. of STAFF15 * INSERT NULL INTO EMPNAME explicitly
DISPLAY" TEST0311 " DISPLAY" CHECK CONSTRAINT " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF15" DISPLAY" VALUES('E1','Alice',52,'Deale');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count1" DISPLAY" FROM STAFF15;" DISPLAY" " DISPLAY" INSERT INTO STAFF15" DISPLAY" VALUES('E1',NULL,52,'Newyork');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count2" DISPLAY" FROM STAFF15;" MOVE 0 TO count1 MOVE 0 TO count2 EXECSQLDELETEFROM STAFF15 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLINSERTINTO STAFF15
VALUES('E1','Alice',52,'Deale') END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLSELECTCOUNT(*) INTO :count1 FROM STAFF15 END-EXEC MOVE SQLCODE TO SQL-COD
EXECSQLINSERTINTO STAFF15
VALUES('E2',NULL,52,'Newyork') END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQLSELECTCOUNT(*) INTO :count2 FROM STAFF15 END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" SQLCODE of second INSERT not equal to 0." DISPLAY" count1 is 1" DISPLAY" count2 is 1" DISPLAY" Your answer is :" DISPLAY" SQLCOD of second INSERT is ", code1 DISPLAY" count1 is ", count1 DISPLAY" count2 is ", count2 if (code1 NOT = 0 AND count1 = 1 AND count2 = 1) then EXECSQLINSERTINTO TESTREPORT
VALUES('0311','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0311','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr004.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD **************** END TEST 0311 **********
******************** BEGIN TEST0312 ******************* *This test checks NOT NULL in table definition con- *straint. * CHECK condition * EMPNAME IS NOT NULL. on STAFF15 * INSERT VALUE INTO all columns except EMPNAME
DISPLAY" TEST0312 " DISPLAY" CHECK CONSTRAINT " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF15" DISPLAY" VALUES('E1','Alice',52,'Deale');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM STAFF15;" DISPLAY" " DISPLAY" INSERT INTO STAFF15(EMPNUM,GRADE,CITY)" DISPLAY" VALUES('E1',52,'Newyork');" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count2" DISPLAY" FROM STAFF15;" COMPUTE count1 = -1 COMPUTE count2 = -1 EXECSQLDELETEFROM STAFF15 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLINSERTINTO STAFF15
VALUES('E1','Alice',52,'Deale') END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLSELECTCOUNT(*) INTO :count1 FROM STAFF15 END-EXEC MOVE SQLCODE TO SQL-COD
EXECSQLINSERTINTO STAFF15(EMPNUM,GRADE,CITY)
VALUES('E2',52,'Newyork') END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQLSELECTCOUNT(*) INTO :count2 FROM STAFF15 END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" SQLCODE of second INSERT not equal to 0." DISPLAY" count1 is 1" DISPLAY" count2 is 1" DISPLAY" Your answer is :" DISPLAY" SQLCOD of second INSERT is ", code1 DISPLAY" count1 is ", count1 DISPLAY" count2 is ", count2 if (code1 NOT = 0 AND count1 = 1 AND count2 = 1) then EXECSQLINSERTINTO TESTREPORT
VALUES('0312','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0312','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr004.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD **************** END TEST 0312 **********
**** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0 STOPRUN.
* **** Procedures for PERFORM statements
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